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8x^2+47x+28=0
a = 8; b = 47; c = +28;
Δ = b2-4ac
Δ = 472-4·8·28
Δ = 1313
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(47)-\sqrt{1313}}{2*8}=\frac{-47-\sqrt{1313}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(47)+\sqrt{1313}}{2*8}=\frac{-47+\sqrt{1313}}{16} $
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